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37 votes
37 votes
Feet is given by h

Layla launches a toy rocket from a platform. The height of the rocket in
-16t² + 136t + 72 where t represents the time
in seconds after launch. How many seconds have gone by when the
rocket is at its highest point?
Answer:
=
seconds
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User Cyril Leroux
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2 Answers

15 votes
15 votes

Final answer:

The time when the rocket is at its highest point is 4.25 seconds.

Step-by-step explanation:

To find the time when the rocket is at its highest point, we need to determine the vertex of the quadratic equation. The equation for the height of the rocket is h = -16t² + 136t + 72. The vertex of a quadratic equation of the form y = ax² + bx + c is given by the formula t = -b/2a. Plugging in the values from our equation, we get t = -136/(2*-16) = 4.25 seconds. So, when the rocket is at its highest point, 4.25 seconds have gone by.

User Shawana
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3.4k points
7 votes
7 votes

Answer:

The time when the rocket is at its highest point is 8.5 seconds.

User Kumar Swamy
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2.8k points