Question

What is the molarity of a 300.0 mL solution containing 25.0 g of NaCl?

Answer 1

1,43 M

Step-by-step explanation:

molair mass NaCl = 58,44 g/mol

You need to calculate how many moles 25 g is:

25 g / 58,44 g/mol = 0,4278 mol

0,4278 mol / 0,3 L = 1,43 M