Final answer:
The balanced complete ionic equation for the reaction between NaOH(aq) and HBr(aq) is Na+(aq) + OH-(aq) + H+(aq) + Br-(aq) → H2O(l) + Na+(aq) + Br-(aq).
Step-by-step explanation:
To write the balanced complete ionic equation for the reaction between NaOH(aq) and HBr(aq), we need to first write the balanced molecular equation, and then break down the reactants and products into their respective ions.
The balanced molecular equation is: NaOH(aq) + HBr(aq) → H2O(l) + NaBr(aq)
Now let's break down the reactants and products into their ions:
NaOH(aq) → Na+(aq) + OH-(aq)
HBr(aq) → H+(aq) + Br-(aq)
H2O(l) → H2O(l)
NaBr(aq) → Na+(aq) + Br-(aq)
Therefore, the balanced complete ionic equation is:
Na+(aq) + OH-(aq) + H+(aq) + Br-(aq) → H2O(l) + Na+(aq) + Br-(aq)