6. If y = -2x² + 8x - 5 were put in vertex form y = a(x - h)² + k, then what is the value of k? A. -13 B. -3 C. 3 D. 1

Casper Lindberg asked Oct 13, 2023

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11 votes

6. If y = -2x² + 8x - 5 were put in vertex form y = a(x - h)² + k, then what is

the value of k?
A. -13
B. -3
C. 3
D. 1

Casper Lindberg asked Oct 13, 2023

3.5k points

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16 votes

Answer:

Explanation:

$y=-2x^2 + 8x-5 \\ \\ =-2(x^2 -4x)-5 \\ \\ =-2(x^2-4x+4-4)-5 \\ \\ =-2((x-2)^2 -4)-5 \\ \\ =-2(x-2)^2 +8-5 \\ \\ =-2(x-2)^2 + 3$

Bcf Ant answered Oct 16, 2023

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