69.2k views
22 votes
Solve the equation (0°≤A≤360°)
a) √3sinA-cosA=√2​

1 Answer

8 votes

Answer:

√3sinA-cosA=√2

dividing both side by (√3²-1²=2 we get)

√3/2 sinA-1/2.cos A=√2/2

cos 30sinA-sin30cosA=√2/(√2×√2)

sinAcos30-cosAsin30=1/√2

sin(A-30)=sin45,sin(180-45)

therefore

A-30=45,135

A=45+30=75 or A=135+30=165

User Caleb Taylor
by
5.9k points