Question

a 70.0kg bicyclist is pedaling to the right, generating a 180n force. she is experiencing a 50.0n drag. neglect any friction impending her motion.

Answer 1

The net force exerted by the bicyclist is 130 N. The acceleration of the bicyclist is 1.86 m/s^2. The force exerted by the bicycle on the ground to produce this acceleration is 130.2 N.

Step-by-step explanation:

The force exerted by the bicyclist can be determined by subtracting the drag force from the applied force. In this case, the applied force is 180 N and the drag force is 50 N. Therefore, the net force exerted by the bicyclist is 180 N - 50 N = 130 N.

The acceleration of the bicyclist can be calculated using Newton's second law, F = ma, where F is the net force and m is the mass. Rearranging the equation, we have a = F/m. Plugging in the values, we get a = 130 N / 70.0 kg = 1.86 m/s2.

So, the force exerted by the bicycle on the ground to produce this acceleration can be determined using the equation F = ma. Plugging in the values, we have F = 70.0 kg * 1.86 m/s2 = 130.2 N.