Final answer:
Using the dilution equation C1V1 = C2V2, it can be determined that 21 mL of the 25% stock hypochlorous acid solution is needed. To make up the final volume of 525 mL, we would then need to add 504 mL of water.
Step-by-step explanation:
The problem presented is a chemistry dilution problem that can be solved using the concept of percent concentration. The medical office needs to prepare 525 mL of a 1% hypochlorous acid solution using a 25% stock solution. To find the amount of the stock solution (V1) needed, we can use the dilution equation C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution required, C2 is the desired concentration, and V2 is the volume of the final solution.
- C1 = 25%
- V2 = 525 mL
- C2 = 1%
Plugging these values into the dilution equation gives:
(25%)V1 = (1%)(525 mL)
V1 = (1% × 525 mL) / 25%
V1 = 21 mL
This means 21 mL of the 25% hypochlorous acid stock solution is required. To get 525 mL of a 1% solution, water would be added up to the final volume. So, the amount of water needed would be:
Water required = V2 - V1 = 525 mL - 21 mL = 504 mL of water.