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A galvanic cell involving the transfer of two electrons has an equilibrium constant of 2.4. What is the electrical potential (in volts) in this cell under standard conditions? Use the simplified equation below.

E∘cell=(0.0592/Vn)logKeq

User Grahame A
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Final answer:

The electrical potential (in volts) of a galvanic cell under standard conditions can be calculated using the Nernst equation. The electrical potential in this case is approximately 0.019 volts.

Step-by-step explanation:

The electrical potential (in volts) of a galvanic cell under standard conditions can be calculated using the Nernst equation. The equation is given as E∘cell = (0.0592/n)logKeq, where E∘cell is the standard cell potential, n is the number of electrons transferred in the cell, and Keq is the equilibrium constant. In this case, the transfer of two electrons and an equilibrium constant of 2.4 are given, so we can substitute these values into the equation to find the electrical potential:

E∘cell = (0.0592/2)log(2.4)

E∘cell = 0.0296log(2.4)

E∘cell ≈ 0.019 V

Therefore, the electrical potential of the galvanic cell under standard conditions is approximately 0.019 volts.

User Mservidio
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