Final answer:
The formula for lithium fluoride is LiF, which reflects the electrical neutrality of the compound with lithium carrying a +1 charge and fluorine a -1 charge. Statement 'd' is incorrect because it reverses these charges, which does not align with their respective electron configurations and tendencies to lose or gain electrons.
Step-by-step explanation:
The formula for lithium fluoride is incorrect in statement 'd' because it suggests that lithium acquires a negative charge and fluorine acquires a positive charge, which is not the case. In reality, when these two elements react to form an ionic compound, the lithium atom loses one electron to achieve a full outer shell, resulting in a lithium ion with a +1 charge (Li+). Similarly, the fluorine atom gains one electron to fill its valence shell, resulting in a fluoride ion with a -1 charge (F-). The correct formula for lithium fluoride is LiF, indicating a 1:1 ratio between Li+ and F- ions, which ensures electrical neutrality of the compound. Additionally, when predicting the formula of an ionic compound formed between a lithium ion and a peroxide ion (O22-), one must use the periodic table to confirm that lithium forms a +1 charge, resulting in the formula Li2O2.