Final answer:
To determine the amount of calcium chloride in a 250.0 mL of a 0.200-M solution, multiply the volume in liters (0.250 L) by the molarity (0.200 M) to find the moles, and then multiply by the molar mass of CaCl2 (110.98 g/mol) to find the mass, resulting in 5.549 grams.
Step-by-step explanation:
The question refers to determining the amount of calcium chloride, or CaCl₂, in grams contained in a 250.0 mL solution with a concentration of 0.200 M. To solve this, we must first calculate the number of moles of CaCl₂ in the solution using the molarity formula:
Moles of CaCl₂ = Volume of solution (L) × Molarity (M)
Here, 0.250 L (since 250.0 mL is equivalent to 0.250 liters) × 0.200 M = 0.050 moles of CaCl₂.
Next, we can determine the mass by utilizing the molar mass of CaCl₂, which is 110.98 g/mol, as follows:
Mass = Moles × Molar Mass
So, 0.050 moles × 110.98 g/mol = 5.549 grams of CaCl₂.
Therefore, 5.549 grams of CaCl₂ are contained in a 250.0 mL of a 0.200-M solution of calcium chloride.