Question

Consider the following code segment.

for (int k = 1; k <= 100; k++)
{
if ((k % 4) == 0)
System.out.println(k);
}

Which of the following code segments will produce the same output as the code segment above?

a.
for (int k=0; k<=7; k=k+2)
{
printf("%5i", k);
}

b.
for (int k=0; k<=8; k=k+2)
{
printf("%5i", k+1);
}

c.
for (int k=1; k<7; k=k+2)
{
printf("%5i", k+1);
}

d.
for (int k=1; k<=8; k=k+2)
{
printf("%5i", k);
}

e.
for (int k=0; k<7; k=k+2)
{
printf("%5i", k);
}

Answer 1

Option d will produce the same output as the given code segment.

Step-by-step explanation:

The code segment that will produce the same output as the given code segment is option d. The given code segment prints out all numbers from 1 to 100 that are divisible by 4. Option d uses a similar logic by starting the loop at 1 and incrementing it by 2, and it prints out all numbers that are odd, which is equivalent to the numbers divisible by 4 in the given code segment.