Question

Which of the following correctly fill /* code */ in method isIt() ?

//method isIt should return true if all of the numbers
//in array are in decreasing ( decending ) order
public static boolean isIt(int[] array)
{
for(int spot=0; spot< -1; spot++)
{
/* code */
return false;
}
return true;
}

a. if( array[spot] < array[spot-1] )

b. if( array[spot-1] < array[spot] )

c. if( array[spot] < array[spot+1] )

d. if( array < array+1 )

e. if( spot < spot+1)

Answer 1

The correct code to fill in the method isIt() is if( array[spot] < array[spot-1] ). This code compares the value at the current spot in the array with the value at the previous spot.

Step-by-step explanation:

The correct code to fill in the method isIt() is a. if( array[spot] < array[spot-1] ). This code compares the value at the current spot in the array with the value at the previous spot. If the current value is smaller than the previous value, the condition is true, indicating that the numbers are in decreasing order.

In the provided code, the for loop iterates through each spot in the array. If, at any point, the current value is not smaller than the previous value, the method returns false, indicating that the numbers are not in decreasing order. If the loop completes without returning false, the method returns true, indicating that all the numbers are in decreasing order.

The correct code option, a. if( array[spot] < array[spot-1] ), ensures that the method correctly checks for decreasing order.