Question

What is returned by the call go(5)?

public static int go(int x)
{
int q=0;
while( x > 0)
{
q = q + x;
x = x - 1;
}
return q;
}

Answer 1

The given code defines a method named go that takes an integer parameter x. It initializes a variable q to 0. The code then enters a while loop that continues as long as x is greater than 0. The code defines a method go that returns the sum of integers from 1 to the given parameter. Calling go(5) will return 15.

Step-by-step explanation:

The given code defines a method named go that takes an integer parameter x. It initializes a variable q to 0. The code then enters a while loop that continues as long as x is greater than 0. In each iteration of the loop, q is incremented by the value of x, and x is decremented by 1. Once x becomes 0 or less, the loop terminates. The value of q is then returned as the result of the method.

If we call go(5) with the given code, it will start with q = 0 and iterate through the loop 5 times. In each iteration, q will be updated by adding the current value of x, starting from 5 and decreasing by 1 in each iteration. So the final value of q will be 5 + 4 + 3 + 2 + 1 = 15.