Final answer:
The Java code snippet provided iterates through an array using a while loop and sums elements based on a non-standard increment pattern. The code terminates with a sum of 32 since the incrementation pattern causes the loop to stop before processing the whole array. Please make sure to include i < arr.length in the while loop condition for it to work properly.
Step-by-step explanation:
The question asks what the following code snippet prints:
int[] arr = {7,2,4,1,5, 8,2,6,10,7};
int sum = 0;
int i = 0;
while(i < arr.length) {
sum += arr[i];
i = arr[i];
}
System.out.println("Sum: "+sum);
This code is written in Java and is iterating through an array using a while loop with a non-standard incrementation pattern. The iteration variable 'i' is set to be the value at arr[i], instead of increasing by one on each iteration. This could potentially cause an infinite loop or an ArrayIndexOutOfBoundsException if the value at arr[i] is equal to or larger than the length of the array (arr.length). However, in this code snippet, since the condition 'i < arr.length' is part of the while loop, it will prevent an ArrayIndexOutOfBoundsException by breaking the loop when 'i' is no longer a valid index of the array.
Working through the loop:
- Iteration 1: i = 0, sum = 7 (arr[0] is 7, so i is updated to 7)
- Iteration 2: i = 7, sum = 13 (arr[7] is 6, so i is updated to 6)
- Iteration 3: i = 6, sum = 15 (arr[6] is 2, so i is updated to 2)
- Iteration 4: i = 2, sum = 19 (arr[2] is 4, so i is updated to 4)
- Iteration 5: i = 4, sum = 24 (arr[4] is 5, so i is updated to 5)
- Iteration 6: i = 5, sum = 32 (arr[5] is 8, so the loop ends because i >= arr.length)
Therefore, the output printed by the code will be 'Sum: 32'.
In this example, please take note that the condition 'i < arr.length' is missing in the presented code. Please make sure to include it for the code to function properly and prevent any potential infinite loops or array index out-of-bounds exceptions.