Question

What is returned by the call go( 10 ) ?

public static String go( int x)
{
String s = "";
for(int n = x; n > -3; n = n - 3)
s = s + n + " ";
return s;
}

Answer 1

The call go(10) returns the string "10 7 4 1 -2 ". It is the result of concatenating the values from a for loop decrementing from 10 by 3 until the value is less than -3.

Step-by-step explanation:

The student is asking about the output of a Java method called go when it is passed the integer value 10. This method is structured with a for loop that decrements the value of n by 3 in each iteration until n is less than -3. The process involves concatenating the current value of n and a space to the string s during each loop iteration. Given the initial value 10, the output can be predicted by examining the loop's behavior.

Here is how the loop will execute:

• Iteration 1: n = 10 (10 is greater than -3), s = "10 "
• Iteration 2: n = 7 (7 is greater than -3), s = "10 7 "
• Iteration 3: n = 4 (4 is greater than -3), s = "10 7 4 "
• Iteration 4: n = 1 (1 is greater than -3), s = "10 7 4 1 "
• Iteration 5: n = -2 (-2 is greater than -3), s = "10 7 4 1 -2 "

After the fifth iteration, the loop ends because the next value of n (which would be -5) is not greater than -3. As a result, the method returns the string "10 7 4 1 -2 ".