Final answer:
The chance of a child having freckles and blonde hair from parents BLT1 (without freckles and with blonde hair) and BLT2 (with heterozygous freckles, and brown hair) cannot be precisely calculated without specific genetic information for brown hair. However, if considering only the B (black) and b (blonde) alleles for hair color in a simplified model, a Punnett square could be constructed, but it still depends on the actual genotype of the brown-haired parent.
Step-by-step explanation:
The chance of the children having freckles and blonde hair can be determined by a dihybrid cross. Freckles (F) are dominant over no freckles (f), and hair color alleles are black (B), brown (not indicated in the question but typically represented with a different letter like Br), and blonde (b), with black being dominant over blonde.
BLT1 (no freckles, blonde hair - ffbb) can only pass on f and b alleles. BLT2 (heterozygous for freckles, brown hair - FfB?) has a combination of F and f alleles but the exact hair color alleles are not clearly defined in the question. Assuming brown hair is a separate allele, we can't determine the exact chances without that information. However, if we consider a simplified model where only B (black) and b (blonde) are considered for hair color, and representing brown hair as either Bb or bb in absence of a distinct allele for brown, then BLT2 can pass on either F or f and B or b.
Setting up the Punnett square:
- The first row/column will have the gametes of BLT1: fb
Without knowing the exact genotype for brown hair, we can't calculate the precise probability for the desired phenotypic combination of freckles and blonde hair.