Answer:
Explanation:
Use formulaic methods. Since she has interest on her money, we have to include it:
i = log(x-4*7)^k
i is the interested amount, x is the variable we use, and k is the number of times. 7 is the interest
i = log(4000-4x7)^2 for 4000 at 7% interest over 2 years
i = log(4000-4x7)^10 for 4000 at 7% interest over 10 years
Amount after 2 years: $30,000
Amount after 10 years: $15,671