Final answer:
The relay input voltage would be 3 V.
Step-by-step explanation:
In this circuit, the analog signal is represented by a 4-20 mA DC current. To find the relay input voltage, we can use Ohm's law. The current flowing through the circuit is 12 mA, which is within the specified range of 4-20 mA. The 250 ohm resistor in parallel with the input terminals of the 1-5 VDC relay creates a voltage drop across the resistor. Using Ohm's law (V = IR), we can calculate the voltage drop as:
V = (I * R) = (0.012 A * 250 Ohm) = 3 V
Therefore, the relay input voltage would be 3 V.