Question

A certain process control system utilizes a tank that is 10 feet tall. The transducer that measures the level of liquid in the tank is located 2 feet from the bottom of the tank. If a 1-5 VDC signal is used to monitor the top 8 feet of water in the tank, how much water is in the tank when the analog value read at the transducer is 3.5 VDC?

Answer 1

The amount of water in the tank when the analog value read at the transducer is 3.5 VDC is approximately 5.25 feet.

Step-by-step explanation:

In this process control system, a 1-5 VDC signal is used to monitor the top 8 feet of water in a tank that is 10 feet tall. The transducer that measures the level of liquid in the tank is located 2 feet from the bottom of the tank. So, when the analog value read at the transducer is 3.5 VDC, we can calculate the amount of water in the tank.

The range of the analog signal corresponds to the top 8 feet of water, which is 5-1=4 feet. The transducer is located 2 feet from the bottom, so the distance from the transducer to the top of the water is 8-2=6 feet.

Using proportion, we can find the amount of water in the tank when the analog value is 3.5 VDC:

(3.5 VDC / 4 VDC) x 6 feet = 5.25 feet.

Therefore, when the analog value read at the transducer is 3.5 VDC, there is approximately 5.25 feet of water in the tank.