Final answer:
To evaluate -3x with x given as 0.027 atm, the result is -0.081. Quadratic equations can be solved using the quadratic formula, whereas cubic equations may require graphing. Exponentials involve adding exponents, and linear equations can be graphed by plotting calculated x,y value pairs.
Step-by-step explanation:
To evaluate the algebraic expression -3x, you need a value for x. From the context of the question, it seems that x has been given the value of 0.027 atm (atmospheres), a unit of pressure. Therefore, substituting 0.027 for x gives us: -3(0.027) = -0.081. The evaluated expression with x = 0.027 atm is -0.081.
When solving other algebraic equations, if you encounter a quadratic equation of the form ax² + bx + c = 0, you can use the quadratic formula which is -b ± √(b² - 4ac) / (2a) to find values for x. In contrast, for cubic equations, there is a different approach as quadratic formula cannot be applied. A method to find zeros for higher-degree polynomials would be graphing, where you could use the zero function on a graphing calculator.
For handling exponentials, remember that when you have expressions like 3².35, you need to separate the integral part of the exponent from the fractional part. For example, 3².35 would expand to (3³) × (3²-.35), which simplifies to 3⁵ as you add the exponents as per the rule xPx˙ = x(p+q).
An equation like y = 9 + 3x is a linear equation representing a straight line on a graph. To analyze this, you should construct a table of values by substituting different values for x and calculating the corresponding y value. This allows you to plot a graph of the equation and helps understand the relationship between x and y visually.