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On a road​ map, the locations​ A, B and C are collinear. Location C divides the road from location A to​ B, such that​ AC:CB = 4​:1 . If location A is at (1,8) and location C is at (-11,0) . Find the coordinate of location B.

On a road​ map, the locations​ A, B and C are collinear. Location C divides the road from location A to​ B, such that​ AC:CB = 2​:1 . If location A is at (-1,-4) and location C is at (-3,-8) . Find the coordinate of location B.

User Repka
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Final answer:

To find the coordinate of location B, we can use the concept of section formula in coordinate geometry. Given that location A is at (-1, -4) and location C is at (-3, -8), and the ratio AC:CB = 2:1, the coordinates of B can be calculated as (-5/3, -16/3).

Step-by-step explanation:

To find the coordinate of location B, we can use the concept of section formula in coordinate geometry. The section formula states that if a point C divides the line segment AB in the ratio m:n, then the coordinates of C can be found using the following formula:

xC = (m * xB + n * xA) / (m + n)

yC = (m * yB + n * yA) / (m + n)

Given that location A is at (-1, -4) and location C is at (-3, -8), and the ratio AC:CB = 2:1, we can substitute these values into the formula to find the coordinates of B.

Let's calculate the coordinates of location B:

xB = (1 * (-3) + 2 * (-1)) / (1 + 2) = (-3 - 2) / 3 = -5/3

yB = (1 * (-8) + 2 * (-4)) / (1 + 2) = (-8 - 8) / 3 = -16/3

Therefore, the coordinate of location B is (-5/3, -16/3).

Without all the specific values for the two scenarios provided by the student, we can use the method outlined above to find the coordinates of B in both cases. Since each scenario has different coordinates for A and C and different ratios for AC:CB, the calculations for B's coordinates will differ. However, the methodology and geometric principles relevant to both problems remain consistent - they are applications of the Section Formula in a division of a line segment in a given ratio.

User BadSantos
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