Question

You calculate that the additive genetic variance for a trait is 5.8774. The total phenotypic variance is 1004.887. What is the narrow-sense heritability (give your answer to three decimal places)?

A. 0.0058
B. 0.025
C. 0.100
D. 0.590

Answer 1

The narrow-sense heritability is calculated as the additive genetic variance divided by the total phenotypic variance. With the given values, the narrow-sense heritability equals 0.005848, rounded to three decimal places. Therefore, the answer is A. 0.0058.

Step-by-step explanation:

To calculate the narrow-sense heritability, which is the proportion of phenotypic variance that is due to additive genetic variance, you use the formula:

h2 = VA / VP

Where:

• VA is the additive genetic variance
• VP is the total phenotypic variance

Given VA = 5.8774 and VP = 1004.887, the narrow-sense heritability is:

h2 = 5.8774 / 1004.887 = 0.005848 (rounded to three decimal places)

The closest answer to this calculation is A. 0.0058.