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Evaluate {x+3y= and 2x-y=1

User Benedicte
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Answer:

So, the solution to the system of linear equations {x + 3y = and 2x - y = 1 is:

x = 3/7 and y = -1/7.

Explanation:

To evaluate the given system of linear equations {x + 3y = and 2x - y = 1, we'll solve for the values of x and y that satisfy both equations.

First, we can solve the second equation for y:

2x - y = 1,

y = 2x - 1.

Now that we have the expression for y in terms of x, we can substitute this into the first equation:

x + 3(2x - 1) = 0,

x + 6x - 3 = 0,

7x = 3,

x = 3/7.

Now that we have the value of x, we can find the corresponding value of y using the expression we found earlier:

y = 2(3/7) - 1,

y = -1/7.

So, the solution to the system of linear equations {x + 3y = and 2x - y = 1 is:

x = 3/7 and y = -1/7.

User Joss Kirk
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