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Find the equation of a line parallel to the line 2x + y -7 =0 and passing through the intersection of the lines x + y -4 = 0 and 2x – y = 8 .

With explanation
Can someone please help me

User MWiesner
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1 Answer

20 votes
20 votes

Answer: y = 2x - 8.

Explanation:

To find the equation of a line parallel to the given line, we need to find the slope of that line. The slope of the line 2x + y - 7 = 0, this can be found by taking the coefficient of the x term and the y term and dividing them. In this case, the slope is 2/1 = 2.

Now that we know the slope of the line we want to find, we can use the slope-intercept form of the line, y = mx + b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis). Since the line we are looking for is parallel to the given line, it will have the same slope, so we can use the same value for m.

The line x + y - 4 = 0 and 2x – y = 8 intersect at the point (4,0). We can use this point to find the value of b in the equation y = 2x + b. Substituting the values from the intersection point, we get 0 = 2(4) + b, which simplifies to b = -8.

Therefore, the equation of the line that is parallel to the given line and passes through the intersection of the two lines is y = 2x - 8.

User Michael Taylor
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