Final answer:
The next outbound leg will be 17 seconds long.
Step-by-step explanation:
The flying pattern described is a holding pattern, where the aircraft flies a specified path in order to maintain its position. In this case, the outbound leg takes 60 seconds and the aircraft turns inbound and crosses the holding fix at 43 seconds. To find the duration of the next outbound leg, we subtract the time it took to cross the fix from the total holding time. So, the next outbound leg would be 60 - 43 = 17 seconds.