Question

IF POSSSIBLE INSERT A DIGIT TO make 13_0 divisible by 6

Answer 1

YAnswer: Yes

Step-by-step explanation: 425 / 5.000

Resultados de traducción

Resultados de traducción

You only have to verify that it is divisible by 2 and by 3. Since it ends in zero (which is an even number) it is divisible by 2. Then it only remains for it to be divisible by 3 and for this the sum of its digits must be a multiple of 3. Therefore, if x is the missing number, we have that 1+3+x+0 must be a multiple of 3. It would suffice, for example, to take x =2 (there are more possibilities as you can see). So one possibility is the number 1320

Answer 2

• Possible digits are 2, 5 or 8

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Divisibility rule by 6:

• It must be an even number and sum of digits must be multiple of 3.

The number 13 x 0 is even number as ends with zero and the sum of its digits is:

• 1 + 3 + x + 0 =
• 4 + x

The x is between 0 and 9.

Possible values of x to make x + 4 a multiple of 3:

• x = 2, then the number is 1320 ⇒ 1320/6 = 220
• x = 5, then the number is 1350 ⇒ 1350/6 = 225
• x = 8, then the number is 1380 ⇒ 1380/6 = 230