Final answer:
The probability that a daughter will be affected by Fabry disease, an X-linked recessive disorder, when her father has the disease, and the mother is a carrier, is 50%.
Step-by-step explanation:
The probability that a daughter of a male with Fabry disease (an X-linked recessive disorder) and a female carrier will be affected is 50%. This is because the disorder is X-linked recessive, which means that males with the defective gene will express the disease, while females must inherit two copies of the defective gene to be affected—one from each parent. In this scenario, the daughter inherits one defective allele from her father and has a 50% chance of inheriting a second defective allele from her carrier mother. Therefore, there is a 50% chance she will be affected by Fabry disease.
When a male with Fabry disease and a female carrier have a daughter, she will have a 50% chance of being a carrier of the disease, just like her mother. However, she will not be affected by the disease. Only males who inherit the disease gene will be affected.
Therefore, the probability that the daughter will be affected by Fabry disease is 0%.