Final answer:
The formula weight of Pb(MnO4)2 is calculated by summing the atomic masses of lead (Pb), manganese (Mn), and oxygen (O), resulting in 445.08 amu.
Step-by-step explanation:
To determine the formula weight of Pb(MnO4)2, we need to calculate the sum of the atomic masses of each atom in the compound. The atomic masses (rounded to two decimal places) for Pb (lead), Mn (manganese), and O (oxygen) are 207.2 u, 54.94 u, and 16.00 u, respectively.
The compound contains one Pb atom, two Mn atoms, and eight O atoms. Therefore, the calculation is as follows:
- Pb: 1 x 207.2 = 207.2 amu
- Mn: 2 x 54.94 = 109.88 amu
- O: 8 x 16.00 = 128.00 amu
Adding these together gives the formula weight:
Pb(MnO4)2 = 207.2 + 109.88 + 128.00 = 445.08 amu