Question

Arrange the liquids pentane (CH3CH2CH2CH2CH3), pentanol (CH3CH2CH2CH2CH2OH), and pentanal (CH3CH2CH2CH2CHO) in order of decreasing viscosity, surface tension, and boiling point.

Rank from highest to lowest viscosity, surface tension, and boiling point.

Answer 1

Following are decreasing order to this question:

Step-by-step explanation:

Viscosity and surface tension both are inter-molecular by nature (IMFs)

The pentane becomes non-polar and just not H-bondable, so LDF alone would be likely (London Dispersion Force)

Pentanal, but H-bond => is impossible (Dipole-Dipole)

Pentanol is also an OH group, so H-bond => is probable (Hydrogen Bonding)

Higher air tension and viscosity than higher IMFs (because the atoms of fluids are more drawn). To lower the IMF (and therefore the viscosity/surface stress decreases)

pentanol

pentanal

pentane