Question

How many grams of krypton gas is contained in a balloon with volume of 2 L if the gas pressure is 3.25 atm and the temperature is 250K? Gas law

Answer 1

There are approximately 26.59 grams of krypton gas in the balloon.

Step-by-step explanation:

The combined gas law relates the pressure, volume, and temperature of a gas. It can be written as:

P₁V₁/T₁ = P₂V₂/T₂

In this question, we are given:

• Volume (V₁) = 2 L
• Pressure (P₁) = 3.25 atm
• Temperature (T₁) = 250 K

To find the number of grams of krypton gas, we first need to calculate the number of moles using the ideal gas law:

n = PV/RT

where n is the number of moles, P is the pressure, V is the volume, R is the ideal gas constant, and T is the temperature. The ideal gas constant is 0.0821 L·atm/(mol·K).

Once we have the number of moles, we can convert it to grams using the molar mass of krypton, which is 83.8 g/mol.

Let's calculate:

1. Calculate the number of moles:
2. n = (3.25 atm * 2 L) / (0.0821 L·atm/(mol·K) * 250 K)
3. Convert moles to grams:
4. grams = moles * molar mass

Substituting the values in the formulas, we get:

1. n = (6.5) / (20.525) = 0.317 moles
2. grams = 0.317 moles * 83.8 g/mol = 26.59 grams

Therefore, there are approximately 26.59 grams of krypton gas in the balloon.