Question

4.
12^2x-1 = (V 12)^x

Answer 1

Explanation:

`12^(2x-1)=(\sqrt[4]{12})^(x)\\\\ 12^(2x-1)= (12^{(1)/(4)})^(x)\\\\12^(2x-1)=12^{(1)/(4)*x}\\`

Bases are same. So, compare the exponents.

`2x - 1 =(1)/(4)x`

Multiply the entire equation by 4

4*(2x - 1) = x

8x - 4 = x

8x = x + 4

8x -x = 4

7x = 4

x = 4/7