Diameter of the circle in the middle = 8 ft
Radius of the circle in the middle :
![=\tt \: (Diameter )/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/q3axlcpthrxzih9idp1z02oseuezw0acfs.png)
![=\tt (8)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/qu6ddh1i60fy1q3taeqa4wi7zveylpkcrl.png)
![=\tt 4 \: ft](https://img.qammunity.org/2022/formulas/mathematics/high-school/h8c2wb2y7ntsm1eqvwi95dcd79lskc92nh.png)
Thus, the radius of the circle in the middle = 4 ft
Area of the entire circle :
![=\tt \pi {r}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/kpdsj1bosygsnx30qy7ql0wpxmcmcmxs67.png)
![= \tt3.14 * 4 + 6 * 4 + 6](https://img.qammunity.org/2022/formulas/mathematics/high-school/naeh4mrgewohxqlpm9lewez39cnhrt7iwz.png)
![= \tt3.14 * 10 * 10](https://img.qammunity.org/2022/formulas/mathematics/high-school/5kgi1ducfm0r1icm5t8yly3w2dr9w68r9n.png)
![=\tt 3.14 * 100](https://img.qammunity.org/2022/formulas/mathematics/high-school/22iojf764rzp6hoqlg0x3xqoupkwmat990.png)
![\color{plum} = \tt314 \: ft](https://img.qammunity.org/2022/formulas/mathematics/high-school/q9ppkjm6m5u4pehlzkze9g3xl271zx3uru.png)
Thus, the area of the entire circle = 314 ft
Area of the circle in the middle :
![=\tt \pi {r}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/kpdsj1bosygsnx30qy7ql0wpxmcmcmxs67.png)
![=\tt 3.14 * 4 * 4](https://img.qammunity.org/2022/formulas/mathematics/high-school/ezm2inrkt46qnjlphr7ji0hlfwa9fma3p7.png)
![= \tt3.14 * 16](https://img.qammunity.org/2022/formulas/mathematics/high-school/jhc0cwtecmlh1pxj8fkr25y6cw5ttuei39.png)
![\color{plum} =\tt 50.24 \: ft](https://img.qammunity.org/2022/formulas/mathematics/high-school/x5ht47wsj0pjldn18ga0jhanpysjqndvry.png)
Thus, the area of the circle in the middle = 50.24 ft
Area of the shaded portion :
= Total area of the figure - Area of the circle in middle
![=\tt 314 - 50.24](https://img.qammunity.org/2022/formulas/mathematics/high-school/pi8frgewmfnfm39h20e9no6b8acwyvcwku.png)
![\color{plum} =\tt 263.76 \: ft](https://img.qammunity.org/2022/formulas/mathematics/high-school/gbmcpa9wnncfgg15jurr1zei39etcfih45.png)
▪︎Therefore, the area of the shaded portion = 263.76 ft