Question

m1 = 4.7 kg m2 = 4.6 kg m3 = 7.8 kg m4 = 3.3 kg d1 between m1 and m4= 0.11 m d2 between m3 and m4= 0.17 m d3 between m1 and m3= 0.2025m the magnitude of the gravitational force between masses m1 and m2 is 4.990×10^-8 N the magnitude of the gravitational force between masses m1 and m4 is 8.550×10^-8 N the magnitude of the gravitational force between masses m1 and m3 is 5.964×10^-8 N What is the magnitude of the gravitational force on mass m1 due to all of the other masses

Answer 1

To determine the total gravitational force on mass m1, sum the individual forces from m1 with other masses. The result is a magnitude of 1.9504×10-7 newtons exerted on m1 by m2, m3, and m4.

Step-by-step explanation:

To calculate the magnitude of the gravitational force on mass m1 due to all of the other masses (m2, m3, m4), we sum up the individual gravitational forces between m1 and each of the other masses using Newton's law of universal gravitation.

The individual forces provided are:

• Force between m1 and m2: 4.990×10-8 N
• Force between m1 and m4: 8.550×10-8 N
• Force between m1 and m3: 5.964×10-8 N

The net force on m1 is simply the sum of these forces:

Fnet on m1 = 4.990×10-8 N + 8.550×10-8 N + 5.964×10-8 N

Fnet on m1 = 1.9504×10-7 N

Therefore, the magnitude of the gravitational force on mass m1 due to m2, m3, and m4 is 1.9504×10-7 newtons.