Question

NOTE: Angles not necessarily drawn to scale.

Answer 1

`\boxed{\tt x=40^(\circ)}`

Explanation:

∠x, ∠BAC, and ∠CAF form a straight line.

*Sum of angles that are formed on a straight line is equal to 180°.*

`\tt \angle x+\angle BAC+\angle CAF=180^(\circ)`

`\tt x+\angle BAC+\angle CAF=180^(\circ)`

`\tt x+80^(\circ)+\angle 60^(\circ)=180^(\circ)`

Add, 80°+60°=140°

`\tt x+140^(\circ)=180^(\circ)`

Subtract 140 from both sides:

`\tt x+140^(\circ)-140^(\circ)=180^(\circ)-140^(\circ)`

`\tt x=40^(\circ)`

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Answer 2

x = 40°

Explanation:

angle A is a vertical angle with 60 so it's 60

60+80 = 140

180-140 = 40