The values of x and y are 5 and 2, respectively.
Because triangles ΔSTU and ΔXYZ are congruent, then we can say that:
m∠S = m∠X
m∠T = m∠Y
m∠U = m∠Z
We already know that mX = 130° and that mX = mS, hence mS = 130°.
We also know that the sum of a triangle's angles equals 180°.
We also know the remaining angles in STU: 28° and (4x+y)°
As a result, S + T + U = 130+28+4x+y = 180. (The degree symbol can be removed)
You can now either enter this as is or simplify it:
130+28+4x+y=180 4x+y+158=180
4x+y=22
The second equation is as follows:
We may use the same method as in the previous equation to find the angles of XYZ:
X = 130, Y = 8x-6y, and Z = 4x+y.
Then combine them and set it to 180:
130+8x-6y+4x+y=180
To simplify, 12x-5y+130=180.
12x-5y=50
To find x and y, do the following:
Now we must deal with the systems.
Let's begin with the first:
4x+y=22
Identify y: y=22-4x (Equation 1)
We then enter it into the second equation:
12x-5y=50
12x-5(22-4x)=50
12x-110+20x=50 32x=160
x=5
So we got x, but to find y, we need to plug in x into Equation 1 (where we isolated y
y=22-4x
y=22-4(5)
y=22-20
y=2
Therefore the values of x and y are 5 and 2, respectively.