Final answer:
The ordered pair that makes both inequalities y < 3x – 1 and y > –x + 4 true will lie in the overlapping region where y is less than 3x – 1 and greater than –x + 4.
Step-by-step explanation:
To find which ordered pair makes both inequalities true, we need to consider the system of inequalities:
We can graph these inequalities to determine where their solution sets intersect. For the first inequality, y < 3x – 1, the graph is a region below the line y = 3x – 1. For the second inequality, y > –x + 4, the graph is a region above the line y = –x + 4. The solution to the system will be the area where these two regions overlap. By visually examining or testing points within these regions, we find the set of points that satisfy both inequalities, namely the ordered pairs that are both above the line y = –x + 4 and below the line y = 3x – 1.
It’s important to note that the exact ordered pair that satisfies both inequalities would need to be determined by further analysis or graphing. Therefore, we cannot provide a specific answer without additional graphical or computational work.