Question

2 10/20 + -3 15/20 + 5 8/20

Answer 1

let's firstly convert the mixed fractions to improper fractions and then add them up.

`\stackrel{mixed}{2(10)/(20)}\implies \cfrac{2\cdot 20+10}{20}\implies \stackrel{improper}{\cfrac{50}{20}} ~\hfill \stackrel{mixed}{3(15)/(20)}\implies \cfrac{3\cdot 20+15}{20}\implies \stackrel{improper}{\cfrac{75}{20}} \\\\\\ \stackrel{mixed}{5(8)/(20)}\implies \cfrac{5\cdot 20+8}{20}\implies \stackrel{improper}{\cfrac{108}{20}} \\\\[-0.35em] ~\dotfill`

`2(10)/(20)-3(15)/(20)+5(8)/(20)\implies \cfrac{50}{20}-\cfrac{75}{20}+\cfrac{108}{20}\implies \cfrac{50-75+108}{20} \\\\\\ \cfrac{83}{20}\implies 4(3)/(20)`