Question

Analyze the following code:

public class Test {
public static void main(String[] args) {
int[] oldList = {1, 2, 3, 4, 5};
reverse(oldList);
for (int i = 0; i < oldList.length; i++)
System (oldList[i] + " ");
}
public static void reverse(int[] list) {
int[] newList = new int[ ];
for (int i = 0; i < ; i++)
newList[i] = list[ - 1 - i];
list = newList;
}
}
(a) The program displays 1 2 3 4 5
(b) The program displays 1 2 3 4 5 and then raises an ArrayIndexOutOfBoundsException
(c) The program displays 5 4 3 2 1
(d) The program displays 5 4 3 2 1 and then raises an ArrayIndexOutOfBoundsException
(e) The program displays 54321 and does not raise an arrayIndexOutOfBoundsException.

Answer 1

The code is expected to reverse an array, but due to issues with array reference handling in Java and missing code details, it will print the original array in order as 1 2 3 4 5.

Step-by-step explanation:

The code provided is attempting to reverse an array of integers. The reverse function initially appears to be missing some critical elements, such as the size of the new array and the loop termination condition. Moreover, even after fixing those issues, assigning newList to list inside the function will not change the original array outside the function due to the way Java handles references to objects in methods. Therefore, even if the reverse function were complete and correctly written, the changes would not be reflected when oldList is printed in the main method. The original array oldList would still display in its initial order, which is 1 2 3 4 5.