Final answer:
The code will compile without error and will print 3 when run.
Step-by-step explanation:
The code will compile without error and will print 3 when run.
The given code snippet is a do-while loop that starts by setting the boolean variable b to false and the integer variable i to 1.
The loop then increments the value of i by 1 and toggles the value of b using the logical NOT operator (!). This process continues as long as b remains true. Since b is always true after the first iteration, the loop will run three times, resulting in i being incremented to 4. The final value is then printed, which is 3.