Question

What is the output of the following code:

class eq
{
public static void main(String args[])
{
String s1 = "Hello";
String s2 = new String(s1);
System.out.println(s1==s2);
}
}
(a) true
(b) false
(c) 0
(d) 1
(e) Hello.

Answer 1

The Java code compares two strings using the == operator, which checks for memory location rather than content. Since one string is created in the string pool and the other through the new keyword, they have different memory addresses. Therefore, the output is false.

Step-by-step explanation:

The code provided demonstrates a fundamental concept in Java related to how strings are stored and compared. When a new string is created using the new keyword, it is stored in a separate memory location compared to the string literal. The == operator in Java is used to compare memory locations when used with objects, rather than comparing the actual content of the objects.

In this case, s1 points to the string literal "Hello" in the string pool, while s2 is a new String object with the same content but is located at a different memory address because of the new operator. Therefore, when s1==s2 is evaluated, it checks if s1 and s2 refer to the same memory location, which they do not. Hence, the output will be false as both have different memory locations.