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13 votes
13 votes
How much energy (in kJ) is gained by iron when a 24.6 g sample is heated from 23.0°C to 99.8°C. The specific heat capacity of iron is 0.387 J/(g*°C)

User Thiagolr
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1 Answer

13 votes
13 votes

Answer:

7.31 x 10⁵ kJ

Step-by-step explanation:

To find the energy gained by the iron sample, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = T₂ - T₁ = change in temperature (°C)

T₂ represents the final temperature and T₁ represents the initial temperature. After you calculate the value of "Q", you need to convert the energy from joules (J) to kilojoules (kJ).

Q = ? J c = 0.387 J/g°C

m = 24.6 g ΔT = 99.8°C - 23.0°C = 76.8°C

Q = mcΔT <----- Equation

Q = (24.6 g)(0.387 J/g°C)(76.8°) <----- Insert values

Q = 731 J <----- Multiply

1,000 J = 1 kJ

731 J 1 kJ
-------------- x ------------------- = 7.31 x 10⁵ kJ
1,000 J

User Baobobs
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