166k views
0 votes
What is the remainder of x^5 - 23^3 + 11x^2 - 14x + 20 when divided by x+5

1 Answer

4 votes

Answer:

115.

Explanation:

Use the Remainder Theorem.

To find the remainder we plug x = -5 into the expression and calculate its value..

So we have:

(-5)^5 - 23(-5)^3 + 11(-5)^2 - 14(-5) + 20

= -3125 + 2875 + 275 + 70 + 20

= -3125 + 3240

= 115.

User Beccari
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories