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What is the remainder of x^5 - 23^3 + 11x^2 - 14x + 20 when divided by x+5

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4 votes

Answer:

115.

Explanation:

Use the Remainder Theorem.

To find the remainder we plug x = -5 into the expression and calculate its value..

So we have:

(-5)^5 - 23(-5)^3 + 11(-5)^2 - 14(-5) + 20

= -3125 + 2875 + 275 + 70 + 20

= -3125 + 3240

= 115.

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