Answer:
200.4 at 0.25%
Explanation:
Given data
P= P200
r= 0.25%
t= 1 year
n= 12
A= P(1+ r/n)^nt
substitute
A= 200(1+ 0.0025/12)^12*1
A= 200(1+ 0.00020833333)^12
A= 200(1.0002)^12
A= 200* 1.002
A= 200.4
Hence the amount is 200.4 at 0.25%
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