Answer:
The football will hit the ground 2.11 seconds later.
Explanation:y = y0 + v0yt + ½ayt
2
0 = v0sin t + ½ayt
0 = t(v0sin + ½ayt)
t = 0 or v0sin + ½ayt = 0
½ayt = – v0sin
=
−20sin
−2(18.0)sin(35.0°)
−9.8
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