Final answer:
The statement suggesting that list.remove("E") would have the same effect as list.remove(5) is False. In the given LinkedList, the index of "E" is 4, not 5; therefore, removing "E" would not be the same as removing the element at index 5.
Step-by-step explanation:
The question relates to the indices of elements within a LinkedList in Java. In a LinkedList, each element is indexed starting from 0. Since the list contains [A, B, C, D, E, F], the index of each letter corresponds to its position in the list - A(0), B(1), C(2), D(3), E(4), and F(5). If we are referring to the removal methods in the LinkedList class, remove(Object o) will remove the first occurrence of the specified element from the list, while remove(int index) will remove the element at the specified position in this list. Therefore, calling list.remove("E") would remove the element "E", which is at index 4, not 5. Thus, the equivalent remove method by index for removing "E" would be list.remove(4) instead of list.remove(5). The statement is False because list.remove("E") does not have the same effect as list.remove(5), which would in fact remove 'F'.