Question

A linked list of Strings named list has been declared and initialized.

Assume that the following code is run on list:
(""3"");list.addFirst(""1"");list.addLast(""2""); (0);list.addFirst(""7""); (""3"");list.addFirst(""6"");list.addLast(""4""); (3);list.addFirst(""2"");list.addFirst(""3""); (""7"");list.addLast(""0"");list.addLast(""9"");
What does (5) return?

Answer 1

The code performs various operations on a linked list of Strings. (5) refers to the element at index 5 in the updated list, which is "3".

Step-by-step explanation:

The given code snippet represents the operations performed on a linked list of Strings named list.

Let's break down the code:

1. The initial list is: "3"
2. list.addFirst("1") adds "1" at the beginning of the list. The updated list is: "1", "3"
3. list.addLast("2") adds "2" at the end of the list. The updated list is: "1", "3", "2"
4. list.addFirst("7") adds "7" at the beginning of the list. The updated list is: "7", "1", "3", "2"
5. list.addFirst("6") adds "6" at the beginning of the list. The updated list is: "6", "7", "1", "3", "2"
6. list.addLast("4") adds "4" at the end of the list. The updated list is: "6", "7", "1", "3", "2", "4"
7. list.addFirst("2") adds "2" at the beginning of the list. The updated list is: "2", "6", "7", "1", "3", "2", "4"
8. list.addFirst("3") adds "3" at the beginning of the list. The updated list is: "3", "2", "6", "7", "1", "3", "2", "4"
9. list.addLast("0") adds "0" at the end of the list. The updated list is: "3", "2", "6", "7", "1", "3", "2", "4", "0"
10. list.addLast("9") adds "9" at the end of the list. The updated list is: "3", "2", "6", "7", "1", "3", "2", "4", "0", "9"

(5) in the context of the code represents the index number. Since indexing starts from 0, (5) refers to the element at index 5 in the list, which is "3".