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If sin (x) =2/5 and tan(x) > 0, what is sin(2x)?

If sin (x) =2/5 and tan(x) > 0, what is sin(2x)?-example-1
User Boombox
by
7.2k points

1 Answer

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Answer:

sin2x =
(4√(21) )/(25)

Explanation:

Given sinx =
(2)/(5) =
(opposite)/(hypotenuse)

Then the third side, the adjacent is found using Pythagoras' identity, that is

adj² + opp² = hyp²

adj² + 2² = 5²

adj² + 4 = 25 ( subtract 4 from both sides )

adj² = 21 ( take the square root of both sides )

adj =
√(21) , then

cosx =
(adj)/(hyp) =
(√(21) )/(5)

Using the double angle identity

sin2x = 2sinxcosx

= 2 ×
(2)/(5) ×
(√(21) )/(5)

=
(4√(21) )/(25)

User Stalskal
by
9.0k points

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