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5 votes
5 terms in sequence 5,16,31,50,73 find and expression for nth term

User JDx
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1 Answer

5 votes

Explanation:

Each term is 11 + (n-2) * 4 more than the previous term


a_(n) =
a_(n-1) + 11 + (n-2)*4 a1 = 5

which can be re-written:


a_(n) =
a_(n-1) + 3 + 4n and a1 = 5 <======answer

User Brian Weiner
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