Final answer:
Jada's collection of fewer than 20 coins is a mix of pennies and nickels that amount to more than 40 cents. By using the individual values of pennies (1 cent) and nickels (5 cents), we can determine various combinations that meet the given conditions.
Step-by-step explanation:
The question pertains to a mathematical problem where Jada has pennies and nickels that together amount to more than 40 cents but less than 20 coins in total. To solve this, we should first understand the value of each coin. A penny is worth 1 cent, and a nickel is worth 5 cents. If Jada had only pennies, she would need more than 40 to have more than 40 cents, but she has fewer than 20 coins. If Jada had only nickels, she would need at least 9 nickels to have more than 40 cents (as 8 nickels are exactly 40 cents). However, she should have a mix of both to satisfy both constraints.
For example, if Jada had 8 nickels (which equals 40 cents) and 1 penny, she would have more than 40 cents with a total of 9 coins. There are other combinations possible, such as 7 nickels (35 cents) and 6 pennies (6 cents) making 41 cents with 13 coins in total. These examples illustrate how we use smaller units (pennies) and larger units (nickels) to make up a certain amount of money.
Therefore, Jada must have more than 15 pennies and less than 7 nickels to have a sum of more than 40 cents and fewer than 20 coins in total.