Answer:
0.975 mole of O₂
Step-by-step explanation:
We'll begin by calculating the number of mole in 80 g of KClO₃. This can be obtained as follow:
Molar mass of KClO₃ = 122.45 g/mol.
Mass of KClO₃ = 80 g
Mole of KClO₃ =?
Mole = mass /Molar mass
Mole of KClO₃ = 80 / 122.45
Mole of KClO₃ = 0.65 mole
Next, we shall write the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Finally, we shall determine the number of mole O₂ produced by the decomposition of 80 g (i.e 0.65 mole) of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, 0.65 mole of KClO₃ will decompose to produce = (0.65 × 3)/2 = 0.975 mole of O₂.
Thus, 0.975 mole of O₂ was obtained from the reaction.